Submission #821387

---

Source Code Expand

//考察1. 1段目が定まったら、2段目以降も一意に定まる。
//考察2. 答えが存在する場合、1段目をどのように決めても条件を満たせる（？）
//解法. 最上段(1行目)を全て0にして、２段目以降を定める。
//1-indexed

#include <stdio.h>

int n;
int now[752][752];
int pre[752][752];

int main() {
	int r, c;
	
	scanf("%d", &n);
	for (r = 1; r <= n; r++) {
		char s[752];
		scanf("%s", s + 1);
		for (c = 1; c <= n; c++) {
			if (s[c] == '#') { now[r][c] = 1; }
			else { now[r][c] = 0; }
		}
	}
	
	for (r = 2; r <= n; r++) {
		for (c = 1; c <= n; c++) {
			pre[r][c] = (((pre[r-2][c] ^ pre[r-1][c-1]) ^ pre[r-1][c+1]) ^ now[r-1][c]);
		}
	}
	
	for (r = 1; r <= n; r++) {
		for (c = 1; c <= n; c++) {
			if (pre[r][c] == 1) printf("#");
			else printf(".");
		}
		puts("");
	}
	return 0;
}

Submission Info

Compile Error

./Main.cpp: In function ‘int main()’:
./Main.cpp:15:17: warning: ignoring return value of ‘int scanf(const char*, ...)’, declared with attribute warn_unused_result [-Wunused-result]
./Main.cpp:18:21: warning: ignoring return value of ‘int scanf(const char*, ...)’, declared with attribute warn_unused_result [-Wunused-result]

Judge Result